tag:blogger.com,1999:blog-1722323236215552391.post4688068024674318123..comments2024-03-25T18:06:04.524-05:00Comments on El Blog del Profe Alex: Derivadas de Logaritmos Naturales - Ejercicios Resueltos - Colección de VideosAlex.Zhttp://www.blogger.com/profile/18226821858170752763noreply@blogger.comBlogger31125tag:blogger.com,1999:blog-1722323236215552391.post-11412219220872167312021-02-27T19:41:18.210-05:002021-02-27T19:41:18.210-05:00X in (2x) derivadas cómo sería X in (2x) derivadas cómo sería Anonymoushttps://www.blogger.com/profile/03661942219105287484noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-37986582183772024242020-10-13T06:49:38.476-05:002020-10-13T06:49:38.476-05:00La derivada sirve para hallar la razon de cambio d...La derivada sirve para hallar la razon de cambio de la función o tambien podría decirse que tan rápido crece o decrece...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-31714819407202168862020-10-13T00:20:36.446-05:002020-10-13T00:20:36.446-05:00Hola, muchos saludos...Una Consulta:
*Nombra un u...Hola, muchos saludos...Una Consulta:<br /><br />*Nombra un uso para la derivación de una función Ln<br />*Para que sirve derivar una función LnJosé Joaquínhttps://www.blogger.com/profile/06054157443730415591noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-9953035159421859382019-07-01T13:22:18.153-05:002019-07-01T13:22:18.153-05:00Buenas tardes me podrían ayudar con derivación num...Buenas tardes me podrían ayudar con derivación numérica <br />F(x)=log(2-1/x) con la formula centradaAnonymoushttps://www.blogger.com/profile/05190025808149478342noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-78567052960193457662017-06-05T20:48:20.805-05:002017-06-05T20:48:20.805-05:00Buenas noches me podrian ayudar con esta analogia
...Buenas noches me podrian ayudar con esta analogia<br /><br />12 (14) 10<br />8 (9) 7<br />5 (?) 4<br /><br />a)6 b)14 c)12 d)4 e)1Anonymoushttps://www.blogger.com/profile/02793071190540923732noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-6265634387629474832017-05-29T17:23:07.681-05:002017-05-29T17:23:07.681-05:00 yooo ln de (x-2) pofa urge
yooo ln de (x-2) pofa urge<br />genny mayhttps://www.blogger.com/profile/13178073216197402186noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-1662367822950180512016-07-03T16:49:46.733-05:002016-07-03T16:49:46.733-05:00Hallar el cuadruplo del valor de x
=>11(6)25
...Hallar el cuadruplo del valor de x <br />=>11(6)25 <br />=>19(X)30rosalinda jazminhttps://www.blogger.com/profile/00564847797872955912noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-15205478523786816222016-07-03T12:51:06.603-05:002016-07-03T12:51:06.603-05:00Hallar el cuadruplo del valor de x
=>11(6)25
...Hallar el cuadruplo del valor de x <br />=>11(6)25 <br />=>19(X)30rosalinda jazminhttps://www.blogger.com/profile/00564847797872955912noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-62692438096895366712015-04-16T22:31:28.593-05:002015-04-16T22:31:28.593-05:00buenas podrian ayudarme con esta derivada
f(x,y)= ...buenas podrian ayudarme con esta derivada<br />f(x,y)= Ln ((x^2 + y^2)^1/2 + x) / ((x^2 + y^2)^1/2 - x)]Juan Carlos Castrohttps://www.blogger.com/profile/07571926992123985618noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-11149322368382073422015-03-24T21:00:50.612-05:002015-03-24T21:00:50.612-05:00hola alguien me puede ayudar http://www.mediafire....hola alguien me puede ayudar http://www.mediafire.com/view/m0966az9ucu8uz4/IMG-20150324-WA0051.jpgAnonymoushttps://www.blogger.com/profile/03642274519343195013noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-2404558515152504652014-11-12T23:01:53.019-05:002014-11-12T23:01:53.019-05:00F(X)=XLN(X) ENTONCES D^2F/DX^2 ES X^2F(X)=XLN(X) ENTONCES D^2F/DX^2 ES X^2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-54288817431555682022014-07-15T20:46:16.980-05:002014-07-15T20:46:16.980-05:00Muchas gracias.Muchas gracias.Anonymoushttps://www.blogger.com/profile/13387621604225521108noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-18234397732392968912014-07-15T07:27:19.572-05:002014-07-15T07:27:19.572-05:00=> 2/(1+x)·Ln(1+x)=> 2/(1+x)·Ln(1+x)Alex.Zhttps://www.blogger.com/profile/18226821858170752763noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-33160613369365459892014-07-14T23:30:38.545-05:002014-07-14T23:30:38.545-05:00Como se deriva esta función?
(L (1+x))^2Como se deriva esta función? <br />(L (1+x))^2Anonymoushttps://www.blogger.com/profile/13387621604225521108noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-27514717375200564012014-04-15T11:20:19.622-05:002014-04-15T11:20:19.622-05:00mmm... mejor has un cambio de base de log -> ln...mmm... mejor has un cambio de base de log -> ln, usa la formula Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-21323174252393890012014-04-15T09:42:35.446-05:002014-04-15T09:42:35.446-05:00Hola oye cuando tengo un logaritmo para derivar , ...Hola oye cuando tengo un logaritmo para derivar , osea <br />derivacion x log (x al 2 + x)<br />Se hacen con las mismas propiedades de los logaritmos naturales?Anonymoushttps://www.blogger.com/profile/09923543727785437795noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-1424803170212643712014-04-08T15:01:24.853-05:002014-04-08T15:01:24.853-05:00hola buena pagina pero quisiera que me ayudaran co...hola buena pagina pero quisiera que me ayudaran con y=9sen(w) de la forma paramétricaAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-89817760220806916922014-03-06T18:18:32.883-05:002014-03-06T18:18:32.883-05:00hola como seria esta derivada? y=ln(2x/x-2)^(1/3) ...hola como seria esta derivada? y=ln(2x/x-2)^(1/3) Anonymoushttps://www.blogger.com/profile/04032829345105522521noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-91623889426136445972014-01-28T01:05:11.207-05:002014-01-28T01:05:11.207-05:00Muchas gracias!Muchas gracias!Anonymoushttps://www.blogger.com/profile/03879835782780601819noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-76273066880514270702014-01-27T13:03:27.862-05:002014-01-27T13:03:27.862-05:00La solución de la derivada puedes verla en: y=ln^...La solución de la derivada puedes verla en: <a href="http://3.bp.blogspot.com/-17r0dPr5wzk/UuaetmR-Z0I/AAAAAAAAJVA/902akI-6aGA/s1600/derivada+log3%28sen2%28tan+3x%29%29.png" rel="nofollow"> y=ln^3 (sen^2 (tg3x)) </a><br />(*) El logarimto natural se está representado por logAlex.Zhttps://www.blogger.com/profile/18226821858170752763noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-41777909154983831322014-01-27T11:01:24.232-05:002014-01-27T11:01:24.232-05:00y=ln^3 (sen^2 (tg3x)) ... Ayuda con esa derivada.....y=ln^3 (sen^2 (tg3x)) ... Ayuda con esa derivada.. no se como hacer el ln al cuboAnonymoushttps://www.blogger.com/profile/03879835782780601819noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-17037078419266437712013-11-09T14:08:39.231-05:002013-11-09T14:08:39.231-05:00La solución de la derivada aquí.
:)<a href="http://www.wolframalpha.com/input/?i=derivate+ln%28ln+tg+x+%29" rel="nofollow">La solución de la derivada aquí.</a><br />:)Alex.Zhttps://www.blogger.com/profile/18226821858170752763noreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-3952464285348799432013-11-09T10:11:56.682-05:002013-11-09T10:11:56.682-05:00como se resuelve ln (ln tg x )como se resuelve ln (ln tg x )Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-44614584142870980442012-12-02T12:58:43.775-05:002012-12-02T12:58:43.775-05:00esta cachonda la profe de mateesta cachonda la profe de mateAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-1722323236215552391.post-21138573709163234392012-02-12T21:36:52.863-05:002012-02-12T21:36:52.863-05:00el profesor de logaritmo basico exprecese mejor i...el profesor de logaritmo basico exprecese mejor irrespetuosoAnonymousnoreply@blogger.com